Question Detail

PHY 102 Test Compilation PHY 102 3 Objective Question
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Question

Inductor connected to 24 V, 50 Hz AC, current 0.5 A. Inductance?
Options
A 48 H
B 12 H
C 0.100 H
D 0.153 H
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

X_L = V/I = 24/0.5 = 48 Ω. X_L = 2πfL → L = 48/(2π×50) = 48/314.16 = 0.1528 H ≈ 0.153 H.

Hint

L = V/(2πfI).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 3
Type: Objective
Difficulty: Not specified
Question 318 of 1819
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