Question Detail
Question
Efficiency of motor: 240 V, 12 A, lifts 600 kg at 0.15 m/s.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Input power = VI = 240×12 = 2880 W. Output power = Fv = mgv = 600×9.8×0.15 = 882 W. Efficiency = 882/2880 = 0.30625 = 30.6%.
Hint
Efficiency = (mgv)/(VI).