Question Detail

PHY 102 Test Compilation PHY 102 4 Objective Question

Question

Series RLC: R=10Ω, L=0.5H, C=10μF. Frequency for max current?
Options
A 50 Hz
B 60 Hz
C 70 Hz
D 71 Hz
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

f = 1/(2π√(LC)) = 1/(2π√(0.5×10×10⁻⁶)) = 1/(2π√(5×10⁻⁶)) = 1/(2π×0.002236) = 1/0.01405 ≈ 71.2 Hz.

Hint

f = 1/(2π√(LC)).

Question Info