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PHY 102 Test Compilation PHY 102 4 Objective Question

Take CBT

1 μF and 2 μF capacitors in series across 1000 V. Voltage across each?

A V1=667 V, V2=333 V

Correct Answer

B V1=250 V, V2=750 V

C V1=750 V, V2=250 V

D V1=1000 V, V2=1000 V

Option A is the correct answer.

C_eq = (1×2)/(1+2)=2/3 μF. Q = C_eqV = (2/3)×1000=666.7 μC. V1 = Q/C1 = 666.7/1=666.7 V, V2 = 666.7/2=333.3 V.

Series: same Q, V = Q/C.

Course: PHY 102

Topic: Test Compilation PHY 102 4

Type: Objective

Difficulty: Not specified

Question 335 of 1819

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