Question Detail

PHY 102 Test Compilation PHY 102 4 Objective Question
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Question

An inductor L=1H in series with R=150Ω, AC source 60V, 50Hz. Phase angle?
Options
A 64.4°
Correct Answer
B 62.1°
C 68.0°
D 58.4°
Correct Answer

Option A is the correct answer.

Detailed Explanation

X_L = 2πfL = 2π×50×1 = 314.16 Ω. tanφ = X_L/R = 314.16/150 = 2.0944 → φ = arctan(2.0944) ≈ 64.5° ≈ 64.4°.

Hint

tanφ = X_L/R.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 4
Type: Objective
Difficulty: Not specified
Question 352 of 1819
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