Question Detail
Question
Electric motor: 240V, 15A, armature resistance 0.15Ω. Power developed in armature?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Back emf E_b = V - IR = 240 - (15×0.15) = 240 - 2.25 = 237.75 V. Power developed = E_b × I = 237.75 × 15 = 3566.25 W ≈ 3566.2 W.
Hint
P_developed = (V - IR) × I.