Question Detail

PHY 102 Test Compilation PHY 102 5 Objective Question
Take CBT

Question

Light bulb: input 50W for 60s, heat produced 2400J. Efficiency?
Options
A 20%
B 80%
Correct Answer
C 12.5%
D 60%
Correct Answer

Option B is the correct answer.

Detailed Explanation

Input energy = 50×60=3000 J. Efficiency = 2400/3000 = 0.8 = 80%.

Hint

η = heat_out / energy_in.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 5
Type: Objective
Difficulty: Not specified
Question 379 of 1819
Previous Course Details Next