Question Detail
Question
Two point charges are separated by a distance of 10 cm. One has a charge of -25µC and the other +50µC. What is the electric field at a point P between the two charges that is 2 cm from the negative charge?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Distance from -25µC = 0.02 m, from +50µC = 0.08 m. E1 = kq1/r1² = (9e9×25e-6)/(0.02)² = 225000/0.0004 = 5.625e8 N/C towards + (since negative charge attracts). E2 = kq2/r2² = (9e9×50e-6)/(0.08)² = 450000/0.0064 = 7.031e7 N/C away from +. Net E = 5.625e8 - 0.7031e8 = 4.92e8 N/C towards positive charge. Option B.
Hint
E = kq/r², vector sum.