Question Detail

PHY 102 Test Compilation PHY 102 5 Objective Question
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Question

Inductor connected to 24V, 50Hz AC, current 0.5A. Inductance?
Options
A 48H
B 12H
C 0.100H
D 0.153H
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

X_L = V/I = 24/0.5 = 48 Ω. L = X_L/(2πf) = 48/(2π×50) = 48/314.16 = 0.1528 H ≈ 0.153 H.

Hint

L = V/(2πfI).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 5
Type: Objective
Difficulty: Not specified
Question 391 of 1819
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