Question Detail

PHY 102 Test Compilation PHY 102 6 Objective Question

Question

Answer saved The resonant frequency of a circuit is 1000 kHz. If each of the capacitance and inductance in the circuit is reduced by 50% and no other changes are made, the resonant frequency will become
Options
A 1000 kHz
B 2000 kHz
Correct Answer
C 100.0 kHz
D 200.0 kHz
Correct Answer

Option B is the correct answer.

Detailed Explanation

f = 1/(2π√(LC)). L→L/2, C→C/2 → LC→LC/4 → √(LC)→½√(LC) → f doubles to 2000 kHz.

Hint

f ∝ 1/√(LC).

Question Info