Question Detail

PHY 102 Test Compilation PHY 102 7 Objective Question
Take CBT

Question

Resistor 20 Ω and inductor 500 mH in series across 120 V, 50 Hz. Current?
Options
A 0.55 A
B 0.76 A
Correct Answer
C 1.69 A
D 2.24 A
Correct Answer

Option B is the correct answer.

Detailed Explanation

X_L = 2πfL = 2π×50×0.5 = 157.1 Ω. Z = √(20² + 157.1²) = √(400 + 24680) = √25080 = 158.4 Ω. I = V/Z = 120/158.4 = 0.757 A ≈ 0.76 A. Option B.

Hint

I = V/√(R² + (2πfL)²).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 7
Type: Objective
Difficulty: Not specified
Question 483 of 1819
Previous Course Details Next