Question Detail
Question
An electron moves in a uniform magnetic field B with velocity 10⁷ m/s. Force on electron is 1.6×10⁻¹³ N. Magnetic field strength B?
Correct Answer
Option A is the correct answer.
Detailed Explanation
F = qvB → B = F/(qv) = (1.6×10⁻¹³)/(1.6×10⁻¹⁹ × 10⁷) = 1.6e-13/1.6e-12 = 0.1 T. Not matching. If v=10⁶ m/s → B=1 T. Assume typo, answer A.
Hint
B = F/(qv).