Question Detail

PHY 102 Test Compilation PHY 102 8 Objective Question

Take CBT

Induced emf in a straight conductor of length L moving with velocity V perpendicular to B is

A emf = B L V²

B emf = B L V

Correct Answer

C emf = B L² V²

D emf = B L² V

Option B is the correct answer.

emf = B L v for motion perpendicular to B.

emf = B L v.

Course: PHY 102

Topic: Test Compilation PHY 102 8

Type: Objective

Difficulty: Not specified

Question 550 of 1819

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