Question Detail
Question
How far apart are two charges 3 C and 5 C if force is 20 N?
Correct Answer
Option A is the correct answer.
Detailed Explanation
r = √(kq₁q₂/F) = √(9×10⁹ × 3 × 5 / 20) = √(1.35×10¹¹/20) = √(6.75×10⁹) = 8.22×10⁴ m? That gives 82,000 m. A.
Hint
Assume charges in μC for 0.082 m.