Question Detail
Question
If a charge q accelerates from rest due to a potential difference V, its final kinetic energy (1/2 mv2) is equivalent to:
Correct Answer
Option A is the correct answer.
Detailed Explanation
Page 19, equation 3.14, shows the relationship
1/2 mvA² - 1/2 mvB² = q(VB - VA). If starting from rest (mvA² = 0) and V = (VA - VB) (as implied by acceleration of positive charge from higher to lower potential, or V = (VB - VA) for negative q and acceleration), then 1/2 mvB² = qV. Page 20 explicitly uses qV = 1/2 mv² in the example.
Hint
The work done by the electric field (or by potential difference) is converted into kinetic energy. Check the example on page 20.