Question Detail

PHY 102 Coulomb's law and Electric Fields Objective Question
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Question

For a parallel-plate capacitor with plate area A, separation d, and a dielectric material with dielectric constant K, what is its capacitance?
Options
A C = Kε₀A/d
Correct Answer
B C = Kε₀d/A
C C = ε₀A/(Kd)
D C = A/(Kε₀d)
Correct Answer

Option A is the correct answer.

Detailed Explanation

Page 12 provides the formula: 'The capacitance of a parallel-plate capacitor whose opposing plate faces, each of area A, are separated by a small distance d is given by C = Kε₀A/d'.

Hint

Recall the direct proportionality to area and inverse proportionality to separation for a parallel-plate capacitor, and how the dielectric constant fits in.

Question Info

Course: PHY 102
Topic: Coulomb's law and Electric Fields
Type: Objective
Difficulty: Not specified
Question 853 of 1819
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