Question Detail

PHY 102 Coulomb's law and Electric Fields Objective Question
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Question

For a parallel-plate capacitor with plate area A, separation d, and a dielectric material with dielectric constant K, what is the formula for its capacitance C?
Options
A <i>C</i> = <i>K</i>ε<sub>0</sub><i>d</i>/<i>A</i>
B <i>C</i> = ε<sub>0</sub><i>A</i>/(<i>Kd</i>)
C <i>C</i> = <i>K</i>ε<sub>0</sub><i>A</i>/<i>d</i>
Correct Answer
D <i>C</i> = <i>K</i>/(ε<sub>0</sub><i>Ad</i>)
Correct Answer

Option C is the correct answer.

Detailed Explanation

Page 12 states the formula for a parallel-plate capacitor as 'C = Kε₀A/d'. This shows that capacitance increases with the dielectric constant and plate area, and decreases with plate separation.

Hint

Capacitance is directly proportional to the area of the plates and inversely proportional to their separation.

Question Info

Course: PHY 102
Topic: Coulomb's law and Electric Fields
Type: Objective
Difficulty: Not specified
Question 867 of 1819
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