Question Detail

PHY 102 Coulomb's law and Electric Fields Objective Question
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Question

For a parallel-plate capacitor with plate area A, separation d, and a dielectric material with dielectric constant K, what is its capacitance?
Options
A C = Kε₀d/A
B C = Kε₀A/d
Correct Answer
C C = ε₀A/(Kd)
D C = KAd/ε₀
Correct Answer

Option B is the correct answer.

Detailed Explanation

The text states: 'The capacitance of a parallel-plate capacitor whose opposing plate faces, each of area A, are separated by a small distance d is given by C = Kε₀A/d' (Page 12, Equation 25.9).

Hint

Check the formula for a parallel-plate capacitor on page 12. Remember that ε₀ is the permittivity of free space.

Question Info

Course: PHY 102
Topic: Coulomb's law and Electric Fields
Type: Objective
Difficulty: Not specified
Question 881 of 1819
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