Question Detail

MTH 102 Differentiation Objective Question

Question

If \( f(x) = \sin^2(3-x) \), find \( f'(0) \).
Options
A \( 2\sin 3 \cos 3 \)
B \( -2\sin 3 \cos 3 \)
Correct Answer
C \( 6\cos 3 \)
D \( 6\sin 3 \cos 3 \)
Correct Answer

Option B is the correct answer.

Detailed Explanation

Apply chain rule: ( f'(x) = 2\sin(3-x) \cdot \frac{d}{dx}(\sin(3-x)) = 2\sin(3-x) \cdot \cos(3-x) \cdot (-1) ). At ( x=0 ), ( f'(0) = -2\sin 3 \cos 3 ).

Hint

Differentiate the outer power, then the sine, then the inside function.

Question Info