Question Detail
Question
What is the second derivative of \( g(x) = \sin(2x^3 - 9x) \)?
Correct Answer
Option A is the correct answer.
Detailed Explanation
( g' = (6x^2 - 9)\cos(2x^3-9x) ). Using product and chain rules: ( g'' = (12x)\cos(2x^3-9x) + (6x^2-9)(-\sin(2x^3-9x) \cdot (6x^2-9)) ).
Hint
Use the chain rule for the first derivative and then the product rule for the second.