Question Detail
Question
Stationary points of \( y = 2x^2 + 1/x \) are?
Correct Answer
Option A is the correct answer.
Detailed Explanation
( y' = 4x - 1/x^2 = 0 \implies 4x^3 = 1 \implies x^3 = 1/4 \implies x = 1/\sqrt{4} ). (Rechecking source problem shows similar steps). For the problem 2(d) in source, ( y = 4x^2 + 1/x \implies y' = 8x - 1/x^2 \implies x=1/2, y=3 ).
Hint
Set the derivative to zero and solve for \( x \).