Question Detail
Question
At what displacement (x) are the kinetic and potential energies equal for an object in Simple Harmonic Motion (SHM)?
Correct Answer
Option B is the correct answer.
Detailed Explanation
From Worked Example 40 (page 43), for K.E = P.E, we have ½mv² = ½kx². Also, E_T = ½kA² = K.E + P.E = 2 * P.E = 2 * (½kx²) = kx². So, ½kA² = kx², which simplifies to A² = 2x², or x² = A²/2. Therefore, x = A/√2.
Hint
Set the potential energy (P.E = ½kx²) equal to the kinetic energy (K.E = ½mv²) and use the total energy relationship (E_T = ½kA²).