Question Detail
Question
If the angular frequency ω = 640°/s and the initial phase φ = 45°, at what time will the phase of the oscillator be 360°?
Correct Answer
Option B is the correct answer.
Detailed Explanation
From Worked Example 3 (page 27), the phase of the oscillator is given by θ = ωt + φ. We want to find t when θ = 360°. So, 360° = (640°/s)t + 45°. Rearranging for t: t = (360° - 45°) / (640°/s) = 315° / 640°/s ≈ 0.492 s.
Hint
Use the formula for the phase of an oscillator: θ = ωt + φ. Substitute the given values and solve for t.