Question Detail
Question
If an oscillator has an angular frequency ω = 640°/s and an initial phase φ = 45°, at what time (in seconds) will the phase of the oscillator be 360°?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The phase of the oscillator is given by θ = ωt + φ. We are given θ = 360°, ω = 640°/s, and φ = 45°. So, 360° = (640°/s) * t + 45°. Subtracting 45° from both sides gives 315° = (640°/s) * t. Therefore, t = 315° / 640°/s = 0.492 s.
Hint
Use the formula for phase as a function of time: θ = ωt + φ.