Question Detail
Question
An observer moves towards a stationary sound source that emits a frequency of 500 Hz. If the observer's speed is 15 m/s and the speed of sound in the medium is 330 m/s, what is the frequency observed by the observer?
Correct Answer
Option C is the correct answer.
Detailed Explanation
For an observer moving towards a stationary source, the observed frequency (f') is given by the Doppler effect formula: f' = f * (v + v_o) / v, where f is the source frequency, v is the speed of sound, and v_o is the observer's speed.Given f = 500 Hz, v_o = 15 m/s (towards), v = 330 m/s.f' = 500 Hz * (330 m/s + 15 m/s) / 330 m/sf' = 500 Hz * (345 / 330) = 500 Hz * (69 / 66) ≈ 522.73 Hz.
Hint
Apply the Doppler effect formula for an observer moving towards a stationary source. Remember that motion 'towards' increases the observed frequency.