Question Detail
Question
According to the inverse-square law for sound intensity, if the distance from a sound source doubles, how does the sound intensity change?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The text states 'I ∝ 1/r^2'. If r doubles (2r), then I ∝ 1/(2r)^2 = 1/(4r^2), meaning the intensity becomes one-fourth.
Hint
Remember the 'inverse-square' relationship with distance.