Question Detail

CHM 102 Practice Questions Objective Question
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Question

Which of the following compounds will be optically active?
Options
A Propanoic acid
B 3-Chloropropanoic acid
C 2-Chloropropanoic acid
Correct Answer
D 3-Chloropropene
Correct Answer

Option C is the correct answer.

Detailed Explanation

2-Chloropropanoic acid (CH3-CHCl-COOH) has a chiral center at C2 (attached to H, CH3, Cl, and COOH), making it optically active. The other compounds lack a chiral center.

Hint

Which compound has a carbon attached to four different groups?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1011 of 1999
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