Question Detail

CHM 102 Practice Questions Objective Question
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Question

Optical isomerism is shown by
Options
A n-Butyl chloride
B sec-Butyl chloride
Correct Answer
C tert-Butyl chloride
D Isobutyl chloride
Correct Answer

Option B is the correct answer.

Detailed Explanation

sec-Butyl chloride (CH3-CHCl-CH2-CH3) has a chiral center at C2 (attached to Cl, H, CH3, and CH2CH3), making it optically active. The other isomers lack a chiral center.

Hint

Which butyl chloride has a carbon attached to four different groups?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1014 of 1999
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