Question Detail
Question
Which halogen does not appreciably react with methane in a free-radical substitution reaction?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Iodine does not appreciably react with methane in free-radical substitution because the reaction is thermodynamically unfavorable (endothermic). The I-I bond is weak, but the H-I bond formed is also weak, making the overall reaction not favorable.
Hint
Which halogen has the weakest H-X bond formed?