Question Detail

CHM 102 Practice Questions Objective Question
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Question

1,2-Dichloroethane reacts with excess of NaNH2 to form
Options
A Vinyl chloride
B Ethylene
C Ethyl chloride
D Acetylene
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

1,2-Dichloroethane (ClCH2-CH2Cl) reacts with excess NaNH2 (strong base) to undergo double dehydrohalogenation, eliminating two equivalents of HCl to form acetylene (HC≡CH).

Hint

What is the product of double dehydrohalogenation of a vicinal dihalide?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1168 of 1999
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