Question Detail

CHM 102 Practice Questions Objective Question

Question

n-Propyl iodide reacts with sodium ethoxide to give :
Options
A CH3CH2OCH2CH3
B CH3CH2OCH2CH2CH3
Correct Answer
C CH3CH2OCH3
D CH3OCH2CH2CH3
Correct Answer

Option B is the correct answer.

Detailed Explanation

n-Propyl iodide (CH3CH2CH2I) reacts with sodium ethoxide (CH3CH2ONa) via SN2 to give ethyl propyl ether (CH3CH2OCH2CH2CH3). This is a Williamson ether synthesis.

Hint

What ether is formed from n-propyl iodide and sodium ethoxide?

Question Info