Question Detail

CHM 102 Practice Questions Objective Question
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Question

How should CH3CHClCH2CH3 be classified?
Options
A primary alkyl halide
B secondary alkyl halide
Correct Answer
C tertiary alkyl halide
D quarternary alkyl halide
Correct Answer

Option B is the correct answer.

Detailed Explanation

CH3CHClCH2CH3 (2-chlorobutane) has the chlorine attached to C2, which is bonded to two other carbon atoms (C1 and C3), making it a secondary alkyl halide.

Hint

How many carbon atoms is the carbon with Cl bonded to?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1226 of 1999
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