Question Detail

CHM 102 Practice Questions Objective Question
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Question

Hydroboration-oxidation of propene gives :
Options
A Isopropyl alcohol
B n-Propyl alcohol
Correct Answer
C Isobutyl alcohol
D tert-Butyl alcohol
Correct Answer

Option B is the correct answer.

Detailed Explanation

Hydroboration-oxidation of propene (CH3CH=CH2) gives n-propyl alcohol (propan-1-ol, CH3CH2CH2OH). This is anti-Markovnikov addition of water, with the OH adding to the less substituted carbon (terminal carbon).

Hint

What is the anti-Markovnikov product of hydration of propene?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1280 of 1999
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