Question Detail

CHM 102 Practice Questions Objective Question

Question

Diethyl ether reacts with excess of hot concentrated HI to form
Options
A CH3CH2I + CH3CH2OH
B Only CH3CH2OH
C CH3CH2OH + CH2=CH2
D Only CH3CH2I
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

With excess hot concentrated HI, the initially formed ethanol reacts further with HI to give ethyl iodide. So the final product is only ethyl iodide.

Hint

What happens to the alcohol formed when excess HI is present?

Question Info