Question Detail

CHM 102 Practice Questions Objective Question

Question

In solution, glucose exists as .
Options
A the open-chain form only
B the cyclic hemiacetal form only
C the cyclic acetal form only
D an equilibrium mixture of the open-chain form and cyclic hemiacetal forms
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

In solution, glucose exists as an equilibrium mixture of the open-chain aldehyde form and cyclic hemiacetal forms (α and β pyranose/furanose).

Hint

What forms does glucose exist in solution?

Question Info