Question Detail

CHM 102 Practice Questions Objective Question
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Question

Reduction of p-nitrotoluene with Sn + HCl gives :
Options
A p-methylaniline
Correct Answer
B Toluene
C m-methylaniline
D N-Methylaniline
Correct Answer

Option A is the correct answer.

Detailed Explanation

Reduction of p-nitrotoluene (CH3-C6H4-NO2) with Sn/HCl reduces the nitro group to an amino group, giving p-methylaniline (p-toluidine).

Hint

What amine is formed from reduction of p-nitrotoluene?

Question Info

Course: CHM 102
Topic: Practice Questions
Type: Objective
Difficulty: Not specified
Question 1705 of 1999
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