Question Detail
Question
Given an urn with 3 red (R) and 2 blue (B) balls, if we draw 2 balls without replacement, what is the probability that both balls are red (P(R1R2))?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Slide 17 calculates P(R1R2) = P(R1) * P(R2|R1) = (3/5) * (2/4) = 6/20 = 0.3.
Hint
This is a multiplication rule problem where the first draw affects the second draw's probabilities.