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STA 112 PERMUTATIONS AND COMBINATIONS Objective Question

Question

How many ways are there to arrange the letters of the word “GARDEN” with the vowels in alphabetical order?
Options
A 120
B 360
Correct Answer
C 720
D 240
Correct Answer

Option B is the correct answer.

Detailed Explanation

The word GARDEN has 6 distinct letters. The vowels are A and E. If the vowels must be in alphabetical order (A before E), we can treat them as identical items when calculating permutations, and then arrange them in the required order. The number of permutations of n objects where p objects are identical is n! / p!. In this case, if A and E were treated as identical for arrangement purposes, the calculation would be 6! / 2! = 720 / 2 = 360. This is because for any arrangement of the 6 letters, only one of the two possible orderings of the vowels (AE or EA) will be alphabetical. Thus, the total arrangements where vowels are in alphabetical order is 6! / (number of permutations of vowels) = 6! / 2! = 360.

Hint

Consider the total permutations of all letters, and then divide by the number of ways the vowels themselves can be arranged if their order didn't matter.

Question Info