Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Find the derivative of y = e^(2x) ln(x + 6)
Options
A e^(2x)/(x+6) + 2ln(x+6)
B e^(2x)/(x+6) + ln(x+6)
C e^(2x) + 2ln(x+6)/(x+6)
D e^(2x)/(x+6) + 2e^(2x) ln(x+6)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Use the product rule: (uv)' = u'v + uv'.Let u = e^(2x) and v = ln(x + 6).Then u' = d/dx(e^(2x)) = e^(2x) * 2 = 2e^(2x).And v' = d/dx(ln(x + 6)) = 1 / (x + 6) * 1 = 1 / (x + 6).Applying the product rule:dy/dx = (2e^(2x)) * ln(x + 6) + e^(2x) * (1 / (x + 6))dy/dx = 2e^(2x) ln(x + 6) + e^(2x) / (x + 6).This matches option D when the terms are reordered.

Hint

Apply the product rule for differentiation, remembering the chain rule for e^(2x).

Question Info