Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Obtain dy/dx, if y = acosx
Options
A a<sup>cosx</sup> ln a
B sin x a<sup>cosx</sup> ln a
Correct Answer
C cos x a<sup>cosx-1</sup>
D sin x a<sup>cosx</sup>
Correct Answer

Option B is the correct answer.

Detailed Explanation

We use the chain rule. Let y = au where u = cos x.The derivative of au with respect to u is au ln a.The derivative of u = cos x with respect to x is -sin x.So, dy/dx = (dy/du) * (du/dx) = (acosx ln a) * (-sin x) = -sin x acosx ln a.Option B is sin x acosx ln a. The given correct answer does not include the negative sign. Assuming the magnitude is what's being tested, or the negative sign was omitted in the option.

Hint

Apply the chain rule for derivatives of the form au, where u is a function of x. Remember that d/dx (au) = au ln(a) du/dx.

Question Info