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MTH 102 MTH 102 Past Questions Objective Question

Question

Obtain ∫(2/(2-3x))dx
Options
A −2ln(2-3x)
B −(2/3)ln(2+3x)
C (2/3)e²−³x
D −(2/3)ln(2-3x)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

This integral can be solved using a u-substitution. Let u = 2-3x.Then, differentiate u with respect to x: du/dx = -3, which implies du = -3dx, or dx = -du/3.Substitute u and dx into the integral:∫(2/u) (-du/3) = (-2/3) ∫(1/u) du.The integral of 1/u is ln|u|. So, we have:(-2/3)ln|u| + C.Substitute back u = 2-3x:(-2/3)ln|2-3x| + C.Option D matches this result.

Hint

Use a u-substitution with u = 2-3x. Remember that ∫(1/u) du = ln|u| + C.

Question Info