Question Detail
Question
Integrate ∫(e³x+8x)dx
Correct Answer
Option D is the correct answer.
Detailed Explanation
Integrate each term separately:
- For ∫e³x dx: The integral of e&sup(ax) is (1/a)e&sup(ax). So, ∫e³x dx = (1/3)e³x.
- For ∫8x dx: Use the power rule for integration. ∫8x dx = 8 * (x²/2) = 4x².
Hint
Remember the integration rule for exponential functions: ∫e&sup(ax) dx = (1/a)e&sup(ax) + C, and the power rule for x&supn;.