Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Given that x = a sin t and y = a cos t, what is y'?
Options
A -tan t
Correct Answer
B tan t
C cot t
D -cot t
Correct Answer

Option A is the correct answer.

Detailed Explanation

To find y' = dy/dx for parametric equations, we use the formula dy/dx = (dy/dt) / (dx/dt).First, find dx/dt and dy/dt:Given x = a sin t, dx/dt = a cos t.Given y = a cos t, dy/dt = -a sin t.Now, calculate dy/dx:dy/dx = (-a sin t) / (a cos t) = -sin t / cos t = -tan t.

Hint

Remember the chain rule for parametric derivatives: dy/dx = (dy/dt) / (dx/dt).

Question Info