Question Detail

This integral can be solved using a simple u-substitution.Let u = 4 + eˣ.Then, differentiate u with respect to x: du/dx = eˣ, which means du = eˣ dx.Substitute these into the integral:∫1/u duThe integral of 1/u is ln|u|.So, ln|u| + C.Substitute back u = 4 + eˣ:ln|4 + eˣ| + C.Since eˣ is always positive, 4 + eˣ is always positive, so we can remove the absolute value signs: ln(4 + eˣ) + C.