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To convert a galvanometer into an ammeter, a small shunt resistance (Rs) is connected in parallel with the galvanometer.Given:Galvanometer resistance (Rg) = 50 ΩFull scale deflection current of galvanometer (Ig) = 2 mA = 2 × 10-3 ADesired full scale current of ammeter (I) = 10 AThe current through the shunt resistance (Is) is I - Ig.Since the shunt is in parallel with the galvanometer, the voltage across them is the same:IgRg = IsRsIgRg = (I - Ig)RsRs = (IgRg) / (I - Ig)Rs = (2 × 10-3 A × 50 Ω) / (10 A - 2 × 10-3 A)Rs = (0.1) / (9.998)Rs ≈ 0.010002 ΩThis value is closest to 0.01 Ω.