Question Detail

PHY 102 Test Compilation PHY 102 10 Objective Question

Question

A galvanometer has spring constant 'k', a magnetic field 'B' and deflection angle Θ. The coil has N turns and an area A. Which of the following is the condition for equilibrium of the coil when current I flows in the galvanometer.
Options
A KB = ΘIAN
B KΘ = BIAN
Correct Answer
C BI = KΘAN
D KΘ = BA/IN
Correct Answer

Option B is the correct answer.

Detailed Explanation

In a moving coil galvanometer, the principle of operation relies on balancing two torques:1. The magnetic torque (τmagnetic) exerted on the coil due to the current flowing through it in a magnetic field. For a coil in a radial magnetic field, this is given by τmagnetic = N I A B, where N is the number of turns, I is the current, A is the area of the coil, and B is the magnetic field strength.2. The restoring torque (τspring) provided by the suspension spring, which opposes the deflection. This is given by τspring = kΘ, where k is the spring constant and Θ is the deflection angle.At equilibrium, these two torques balance each other: τmagnetic = τspring.Therefore, N I A B = kΘ, which can be rearranged as KΘ = BIAN.

Hint

At equilibrium, the magnetic torque on the coil balances the restoring torque of the spring.

Question Info