Question Detail
Question
Calculate the force on a wire of length 5cm carrying a current of 30A if it is placed perpendicular to a magnetic field of intensity 0.8T.
Correct Answer
Option D is the correct answer.
Detailed Explanation
The force (F) on a current-carrying wire in a magnetic field is given by F = BILsin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the current direction and the magnetic field direction.Given:B = 0.8 TI = 30 AL = 5 cm = 0.05 m (since 1m = 100cm)θ = 90° (perpendicular), so sin(90°) = 1F = 0.8 T * 30 A * 0.05 m * 1 = 24 * 0.05 N = 1.2 N.The force on the wire is 1.2 N.
Hint
Use the formula F = BILsin(θ). Remember to convert units to SI.