Question Detail
Question
Calculate the force on a wire of length 5 cm carrying a current of 30 A if it is placed perpendicular to a magnetic field of intensity 0.8 T.
Correct Answer
Option D is the correct answer.
Detailed Explanation
The magnetic force (F) on a current-carrying wire in a magnetic field is given by F = BILsinθ, where B is the magnetic field intensity, I is the current, L is the length of the wire, and θ is the angle between the current direction and the magnetic field. Given L = 5 cm = 0.05 m, I = 30 A, B = 0.8 T, and θ = 90° (perpendicular, so sin 90° = 1).F = (0.8 T) * (30 A) * (0.05 m) * 1 = 1.2 N.
Hint
Ensure all units are consistent (e.g., length in meters) and remember that sin(90°) = 1.