Question Detail

Electric flux (Φ) is given by Φ = E · A = EA cosθ, where E is the electric field strength, A is the area, and θ is the angle between the electric field vector and the area vector (normal to the surface).Given: E = 100 V/m, radius r = 0.025 m.Area A = πr2 = π * (0.025 m)2 = π * 0.000625 m2 ≈ 0.001963 m2.The angle the field lines make with the surface is 30°. Therefore, the angle with the normal to the surface (area vector) is θ = 90° - 30° = 60°.So, cosθ = cos(60°) = 0.5.Φ = E * A * cosθ = 100 V/m * 0.001963 m2 * 0.5Φ = 0.09815 V·m (which is dimensionally equivalent to Nm²/C).Rounding to three decimal places, Φ ≈ 0.098 Nm²/C.