Question Detail

MTH 102 PHY 102 Past Questions Objective Question

Question

A galvanometer has spring constant 'k', a magnetic field 'B' and deflection angle θ. The coil has N turns and an area A. Which of the following is the condition for equilibrium of the coil when current I flows in the galvanometer?
Options
A KB = θIAN
B Kθ = BIAN
Correct Answer
C BI = KθAN
D Kθ = BA/IN
Correct Answer

Option B is the correct answer.

Detailed Explanation

In a galvanometer, the coil experiences a deflecting torque due to the magnetic field and a restoring torque from the spring. At equilibrium, these two torques are equal.The deflecting torque (τdeflect) on a coil in a magnetic field is given by τdeflect = BIANsinα, where B is the magnetic field, I is the current, A is the area of the coil, N is the number of turns, and α is the angle between the normal to the coil and the magnetic field. For a radial magnetic field in a galvanometer, sinα = 1, so τdeflect = BIAN.The restoring torque (τrestore) exerted by the spring is proportional to the deflection angle (θ): τrestore = kθ, where k is the spring constant.At equilibrium, τdeflect = τrestore.Therefore, BIAN = kθ or Kθ = BIAN.

Hint

Equate the magnetic torque on the coil to the restoring torque of the spring.

Question Info